Calculating Compound Interest
How Fast can One's Fortune Grow?
Assume an ideal investor with those variables:
- \(P\) → original principal sum
- \(r\) → nominal annual interest rate
- \(c\) → number of compounding
- \(A_c\) → amount after compounding c times
- \(n\) → compounding frequency for each year (annually compounding means n=1 and monthly compounding means n=12)
- \(\frac{r}{n}\) → nominal interest rate for each compounding
- \(t\) → overall length in year
- \(t\times n\) → total number of compounding
Case 1: without monthly money inflow
Initial condition:
For each compounding:
Hence, after \(t\) years or compounding \(c=t\times n\) times:
Case 1.1: how many years are needed to double an investor's initial fortune?
Assuming an investor is investing low-to-medium risk assets, and luckily he has a stable yearly interest rate of \(r=2\% =0.02\).
For doubling his initial investment, the final amount would be \(A_{t\times n}=2P\).
Thus, it takes the investor \(t\approx 0.69/\ln(1+0.02) \approx 35.00\) years to double his fortune.
Note that the \(\ln\), instead of for example \(\log_{10}\), was used because we can get a simple empirical relationship.
Because \(\ln(1+r)\) approximates \(r\) when the value of r is very small.
The equation can simplify into
$$ t\approx \frac{0.69}{r} \approx \frac{70}{r\%}, $$ which is also called the Rule of 70.
One's fortune doubles per \(\frac{70}{\text{interest percentage point}}\) years.
Case 2: With monthly inflow
The initial asset is still \(P\) but in each month, the investor adds \(w\) into his investment.
For each month, the final amount is
Sequentially, the amount after each month's compounding is
- \(P(1+r/n)\)
- \((P(1+r/n)+w)(1+r/n) = P(1+r/n)^2 + w(1+r/n)\)
- \([P(1+r/n)^2 + w(1+r/n) +w](1+r/n)= P(1+r/n)^3 + w(1+r/n)^2+w(1+r/n)\)
- ...
This can be summerized into
where \(n=12\).
So after one year or 12 compounding, one's fortune would be
References
- https://www.investor.gov/financial-tools-calculators/calculators/compound-interest-calculator
(TODO: Approximation of sequences?)